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number of
variables involved in analyzing them, they can be designed and modeled
more accurately by our experienced engineers using Marlow Industries'
internally developed computer software. For selection of a
thermoelectric cooler with more than two stages, or if more precision is
required, please consult one of our application engineers. Once the
decision to use a thermoelectric cooler has been made, the actual
selection of a suitable thermoelectric cooler is relatively simple. The
following information outlines a step by step procedure that will take
you through determining your heat load, required DT, and the number of
stages required to meet the DT.
Once you have
completed the analysis you will have narrowed the field of suitable TECs
to two or three. You may then proceed to the next section to performance
of the selected TECs within your application requirements.
Proceed
to "Estimating
TEC Performance"
1. Calculate
Heat Loads
| Type of Load |
Example |
Your
Case |
| Active
Load |
8.0 |
_______
watts |
| Radiation
Load |
0.2* |
_______
watts |
| Convective
Load |
0.8* |
_______
watts |
| Conductive
Load |
0.0* |
_______
watts |
| Total
Heat Load |
9.0 |
_______
watts |
* Refer to
section entitled "Estimating
Heat Loads" for information on determining these loads.
2. Define
Temperatures
| Component
Temp |
Example |
Your
Case |
| TEC hot
side (Th) |
27 |
_______
°
C
|
| TEC cold
side (Tc) |
-8 |
_______°C |
| DT(Th-Tc) |
35 |
_______°C |
3. Determine
Number of Stages Required
Select the
minimum number of stages from the table below which will meet the
required DT.
|
Stage
|
D
Tmax
(Dry N2@ 1 atm) |
D
Tmax
(Vacuum) |
|
| 1 |
64 |
67 |
| 2 |
84 |
91 |
| 3 |
95 |
109 |
| 4 |
-- |
115 |
| 5 |
-- |
121 |
| 6 |
-- |
127 |
In
this example, a single-stage TEC will suffice, since 64°C
is greater than the desired 35°C
DT. If the number of stages required exceeds two, the following
selection process is not applicable. These calculations are only
accurate for a one- or two-stage thermoelectric cooler. For three-stage
and above, call one of our applications engineers for assistance.
4. Select an
Appropriate TEC
The performance
graphs used in this brochure have been normalized to provide a universal
curve for use with any single- or two-stage TEC for which the
"Maximum" values are known. By using ratios of actual to
"Maximum" performance values, performance may be estimated
over a wide range of operating conditions.
a. Determine
the ratio of DT/DTmax.
|
Example |
Your
Case |
| DT (from
step 2) |
35°C |
_______°C |
| Dtmax
(from step 3) |
64°C |
_______°C |
| DT/T
max (Calculate)) |
35°/64° |
_______°C |
b. On
the performance graph (Figure 2), draw a horizontal line on the graph
corresponding to DT/DTmax (.55 in this example).
c.
Obtain the Optimum value of Q/Qmax at the intersection of the
horizontal line just drawn and the diagonal Optimum Q/Qmax
line. Interpolation between curves may be necessary.
Optimum
Value of Q/Qmax
|
Example |
Your
Case |
| Optimum Q/Qmax |
0.25 |
______ |
d. Obtain
the Maximum value of Q/Qmax at the intersection of the
horizontal line (drawn in step 4b) and the right vertical axis.
Maximum
Value of Q/Qmax
|
Example |
Your
Case |
| Maximum Q/Qmax |
- .45 |
_______ |
e.
Divide the total heat load (from step 1) by the Q/Qmax
ratios above to calculate the Optimum and Maximum Qmax.
Optimum
Qmax
| Optimum
Qmax |
=
9/0.25 |
=36
watts |
| Optimum
Qmax |
=______/ |
______ |
Maximum
Qmax
| Maximum
Qmax |
=
9/0.45 |
=20
watts |
| Maximum
Qmax |
=______/ |
______ |
f.
Select a TEC from Marlow's standard product list with a Qmax
greater than the Maximum Qmax (20 watts in this example),
but less than the Optimum Qmax (36 watts in this example).
Keep in mind that within this range a TEC with a Qmax close
to the Optimum Qmax will provide maximum efficiency, and a Qmax
close to the Maximum Qmax will yield smaller and possibly
less expensive TECs. Reading down the Qmax column results in
the selection of the following TECs:
Example
TEC Values
| Range
Location |
Model# |
Qmax |
Imax |
Vmax |
| Near
Optimum |
DT6-6 |
30 |
5.6 |
8.2 |
| Nearer
Optimum |
DT6-4 |
20 |
3.7 |
8.2 |
Your
Cae TEC Values
| Model# |
Qmax |
Imax |
Vmax |
| ______ |
______ |
______ |
______ |
| ______ |
______ |
______ |
______ |
For
this example, let us assume maximum efficiency is desired. Thus, the 5.6
amp, 8.2 volt cooler is selected, because between these two potential
TECs, its Qmax (30 watts) is closest to the optimum Qmax (36 watts).
Figure
2

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